If we took EXACTLY 1.00 ml of a 1.000 M solution of Cu(NO3)2 and placed it in 99

Question

If we took EXACTLY 1.00 ml of a 1.000 M solution of Cu(NO3)2 and placed it in 99.000 ml of water and mixed it, then took 2.00 ml of this solution and placed it in 18.000 ml of water. A) What is the concentration (in mol/L or M) of Cu^2+ and NO3^- (minus sign at top) in the final solution? remember significant figures B) Consider an impurity of Cu^2+ in the water you are using to perform the dilutions. What type of error is this associated with the concentration of Cu2+ and why is it so? Please help!! Im so confused!! I appreciate any help with this. Thank you

Explanation / Answer

A)1.11*10^-3 M B)https://www.google.co.in/url?sa=t&rct=j&q=&esrc=s&source=web&cd=2&cad=rja&ved=0CD4QFjAB&url=http%3A%2F%2Fwww.nelsonthornes.com%2Fsecondary%2Fscience%2Fchemistryincontext%2Fpdfs%2Flab_manual_answers.pdf&ei=wN71UKjMKMuUrgfC_YCoDQ&usg=AFQjCNHlXDP0hlj5w-jRSkq7HRjUfnD__A&sig2=cSCjRSb60ew4PtCjqinf7Q&bvm=bv.41018144,d.bmk https://www.google.co.in/url?sa=t&rct=j&q=&esrc=s&source=web&cd=3&cad=rja&ved=0CEcQFjAC&url=http%3A%2F%2Fwww.laspositascollege.edu%2FChemistry%2Fdocuments%2FChem1ALabManualFA12Edition052812.pdf&ei=wN71UKjMKMuUrgfC_YCoDQ&usg=AFQjCNFAqKPwH8bQs3sBg3OV5rY6aBrImg&sig2=QZo2tP9w-gSNGpx5oFhOvw&bvm=bv.41018144,d.bmk

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