1.- Classify thefollowing redox reactions as combination, decomposition ordispla

Question

1.- Classify thefollowing redox reactions as combination, decomposition ordisplacement: a) P4 + 10Cl2 --->4PCl5, b) 2H2O2 ---> 2H2O +O2, c) Mg + 2AgNO3 --->Mg(NO3)2 + 2Ag, d)NH4NO2 ---> N2 +2H2O, e) 2NO --->N2 +O2, f) H2 + Br2 ----> 2HBr. 2.- Calculate the mass of KI in grams required to prepare 5.00x 102 mL of a 2.80 M solution. 3.- How would you prepare 60.0 mL of 0.200 M HNO3from a stock solution of 4.00 M HNO3? 1.- Classify thefollowing redox reactions as combination, decomposition ordisplacement: a) P4 + 10Cl2 --->4PCl5, b) 2H2O2 ---> 2H2O +O2, c) Mg + 2AgNO3 --->Mg(NO3)2 + 2Ag, d)NH4NO2 ---> N2 +2H2O, e) 2NO --->N2 +O2, f) H2 + Br2 ----> 2HBr. 2.- Calculate the mass of KI in grams required to prepare 5.00x 102 mL of a 2.80 M solution. 3.- How would you prepare 60.0 mL of 0.200 M HNO3from a stock solution of 4.00 M HNO3? b) 2H2O2 ---> 2H2O +O2, c) Mg + 2AgNO3 --->Mg(NO3)2 + 2Ag, d)NH4NO2 ---> N2 +2H2O, e) 2NO --->N2 +O2, f) H2 + Br2 ----> 2HBr. 2.- Calculate the mass of KI in grams required to prepare 5.00x 102 mL of a 2.80 M solution. 3.- How would you prepare 60.0 mL of 0.200 M HNO3from a stock solution of 4.00 M HNO3?

Explanation / Answer

     1. a) P4 +10Cl2 ---> 4PCl5   -  Combination reaction           b)2H2O2 ---> 2H2O +O2 - Decomposition reaction          c)  Mg + 2AgNO3 --->Mg(NO3)2 + 2Ag   -  Displacement reaction           d)NH4NO2 ---> N2 +2H2O   - Decomposition reaction           e) 2NO--->N2 + O2     - Decomposition reaction                    f) H2 + Br2 ----> 2HBr.  - Combination reaction      2.     Molarityis the number of moles of solute present in one litre of thesolution .                0.28 M = No. of moles of KI / 0.5 L                     Number of moles of KI = 0.14                   0.14 mol = mass of KI (g) /molar mass                                   = mass / 166.0028 g/mol                      Mass = 23.24 g       3.   According to thedilution formula , M1 V1 = M2V2                   0.2 M * 0.06L = 4.0 M * V                  Volume of the stock solution = 0.003L            Take 0.003 L ( 3 mL ) of 4.0 M stock solution in avolumetric flask and add water up to 60.0 mL

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