At 25 degrees C, Ag2CrO4 is placed in a solution that is0.0050 M K2CrO4. The Ksp

Question

At 25 degrees C, Ag2CrO4 is placed in a solution that is0.0050 M K2CrO4. The Ksp of Ag2CrO4= 1.1*10^-12. Q: The solubility of AG2CrO4 under these conditions is:___________(M) At 25 degrees C, Ag2CrO4 is placed in a solution that is0.0050 M K2CrO4. The Ksp of Ag2CrO4= 1.1*10^-12. Q: The solubility of AG2CrO4 under these conditions is:___________(M)

Explanation / Answer

              Ag2CrO4         2Ag+    +       CrO42- initial                                       0                 0.005 change                                    +2x                 +x equil                                        2x                 0.005 + x Ksp = [Ag+]2[CrO42-] = (2x)2(0.005+x) =1.1e-12 4x2(0.005+x) = 1.1e-12 Assume 0.005 >>x              (see below were x is found to be 7.42e-6, so this is justified) 4x2(0.005) = 1.1e-12 x = (1.1e-12 /4/0.005)0.5 = 7.42 e-6 M (thesolubility)

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