*Submit each part separately to avoid losing your work* Calculate the energy (J)

Question

*Submit each part separately to avoid losing your work* Calculate the energy (J) of the photon emitted when an electron in the hydrogen atom falls from n = 4 to n = 1 . Use 2.178 Times 10-18 J for the constant in the Bohr equation. Answer should be in scientific notation, e.g. 3000 = 3E3 Incompatible units. No conversion found between "m" and the required units. Tries 0/99 Previous Tries Calculate the wavelength (m) of the light emitted during the transition from n = 6 to n = 2 . Hint, first calculate the energy as you did in the previous problem. Again, enter your answer in scientific notation.

Explanation / Answer

E=Eo((n2)-2-(n1)-2)=2.178x10-18(1-1/16)=2E-18 J

E= 2.178x10-18(1/4-1/36)=hc/ h=6.624E-34, c=3E8

=4.1E-7

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.