In acidic aqueous solution, the purple complex io Co(NH3)5Br2+ undergoes a slow

Question

In acidic aqueous solution, the purple complex io Co(NH3)5Br2+ undergoes a slow reaction in which the bromide ion is replaced by a water molecule, yielding the pinkish-orange complex ion : The reaction is first order in Co(NH3)5Br2+, the rate constant at 25 degree C is 6.3 times 10-6 s-1, and the initial concentration of Co(NH3)5Br2+ is 0.100 M What is its molarity after a reaction time of 11.0h ? Express your answer using two significant figures. How many hours are required for 65% of the Co(NH3)sBr2+ to react? Express your answer using two significant figures

Explanation / Answer

a)ln(Ao/A)=kt or ln(0.1/A)=6.3*10^-6*11*60*60 or ln(0.1/A)=0.24948 or A=0.07792 b) ln(100/(100-65)=kt or t=46.288 hours

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