calculate H for the follow ing reaction: 2NH3(g)+3 N2O(g)--->4N2(g) + 3H2O(l) 4N
ID: 76635 • Letter: C
Question
calculate H for the follow ing reaction: 2NH3(g)+3 N2O(g)--->4N2(g) + 3H2O(l) 4NH3+3O2----->2N2+6H2O H = -1531 KJ N2O + H2------->N2+H2O H = 1367.4KJ H2+1/2O2--->H2O H=-285.9KJ calculate H for the follow ing reaction: 2NH3(g)+3 N2O(g)--->4N2(g) + 3H2O(l) 4NH3+3O2----->2N2+6H2O H = -1531 KJ N2O + H2------->N2+H2O H = 1367.4KJ H2+1/2O2--->H2O H=-285.9KJExplanation / Answer
2NH3(g) +3 N2O(g)--->4N2(g) +3H2O(l) Hrxn = Hproducts -Hreactants Hrxn = 3 Hof H2O(l) +4Hof N2(g) - [2Hof NH3(g) +3Hof N2O(g)] Given H2+1/2O2--->H2O H=-285.9KJ HofH2O = -285.9kJ/mol N2O+ H2------->N2+H2O H = 1367.4KJ HofN2O = -1367.4 kJ/mol 4NH3+3O2----->2N2+6H2O H = -1531 KJ Hof NH3(g) = (1531 /4)kJ/mol = 382.75 kJ/mol 2NH3(g) +3 N2O(g)--->4N2(g) + 3H2O(l) Hrxn = [3 (-285.9 kJ/mol) + 4*0] - [2 *382.75kJ/mol + 3*(-1367.4kJ/mol] = -857.7 kJ/mol - 765.5 kJ/mol +4102.2kJ/mol = 2479 kJ/mol HofH2O = -285.9kJ/mol N2O+ H2------->N2+H2O H = 1367.4KJ HofN2O = -1367.4 kJ/mol 4NH3+3O2----->2N2+6H2O H = -1531 KJ Hof NH3(g) = (1531 /4)kJ/mol = 382.75 kJ/mol 2NH3(g) +3 N2O(g)--->4N2(g) + 3H2O(l) Hrxn = [3 (-285.9 kJ/mol) + 4*0] - [2 *382.75kJ/mol + 3*(-1367.4kJ/mol] = -857.7 kJ/mol - 765.5 kJ/mol +4102.2kJ/mol = 2479 kJ/molRelated Questions
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