5. Assume that the partition coefficient, K, for partitioning of compound Abetwe

Question

5. Assume that the partition coefficient, K, for partitioning of compound Abetween diethyl ether and water is 3; that is, A preferentially partitions into ether. a. Given 400 mL of an aqueous solution containing 12 g of compound A, how many grams of A could be removed from the solution by a single extraction with 200 mL of diethyl ether? b. How many total grams of A can be removed from the aqueous solution with three successive extractions of 67 mL each? *if given the equation can you please explain how you got it and what the numbers mean in it (if some numbers or standard or the plug in's you took from the question I asked you ) -thanks :)

Explanation / Answer

According to the formula
[A]aqfinal/ [A]aq initial= [(V2/(V2+V1K)]^n
V2 / V1 = 2 (given as 400 / 200)
X/1= ( 1/ (1+2(3))^2 X=0.0156
=0.0156 * 100 = 1.56%
Percentage separation = 100 -- 1.56 = 98.44 %
Part A) Separation = 12 * 98.44 / 100= 11.81 grams.
Part B) Now V2 / V1 has been changed to 5.97:1 as, 400:67
so, X1= ( 6/ (6+1(3))^2 X1= 0.074 = 7.4%
percentage removal= 100 - 7.4 % = 92.6 %
so, 3 step removal removal = step 1: 12 * (92.6 / 100) =11.112 grams.

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