a. an aqueous solution of antifreeze contains 6.067 M ethyleneglycol (HOCH 2 CH

Question

a. an aqueous solution of antifreeze contains 6.067 M ethyleneglycol (HOCH2CH2OH, 62.07 g/mol) and has adensity of 1.046 g/mL. Find the mass of 1.00L of this solution andthe number of grams of ethylene glycol per liter. b.How many grams of 50wt%(weight percent) NaOH (40.00 g/mol)solution should be diluted to 1.00 L to make 0.10 M NaOH? a. an aqueous solution of antifreeze contains 6.067 M ethyleneglycol (HOCH2CH2OH, 62.07 g/mol) and has adensity of 1.046 g/mL. Find the mass of 1.00L of this solution andthe number of grams of ethylene glycol per liter. b.How many grams of 50wt%(weight percent) NaOH (40.00 g/mol)solution should be diluted to 1.00 L to make 0.10 M NaOH?

Explanation / Answer

We Know that :       Molarity = number of moles ofsolute / volume of the solution         6.067 M = number of moles / 1.0 L          number ofmoles = 6.067 mol           weightof the substance = 6.067 mol x 62.07 g / mol                                                = 376.57 g           so 376.57 g of ethylene glycol is present in per litre of thesolution           mass of the substance = 1.046 g / ml x 1000 ml                                               = 1046 g      b.               0.10 = 0.5 x weight of NaOH / 40.0 g /mol / 1 L              weight of NaOH required = 8 gm                    

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