1-Small quantities of oxygen can be prepared in the laboratory by heating potass
ID: 770417 • Letter: 1
Question
1-Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s). The equation for the reaction is kclo3 2kcl----2kcl+3o2 Calculate how many grams of O2(g) can be produced from heating 55.3 grams of KClO3(s). 2-The combustion of propane may be described by the chemical equation, C^3H^8(g)+3Co^2(g)+4H^2O(g) How many grams of O2(g) are needed to completely burn 72.3 g of C3H8(g)? 3-Here is the combustion reaction for octane (C8H18), which is a primary component of gasoline 2C^8H^18+25O^2 ---- 16Co^2+18H^2O . How many moles of CO2 are emitted into the atmosphere when 16.6 g of C8H18 is burned? Please ...Explanation / Answer
Molar mass of KClO3 : 122.55 g/mol
moles of KClO3= 0.4512 moles
moles of oxygen produced = 3*0.4512=1.3537moles
grams of O2= 1.3537moles*16=21.65 g
molar mass of C3H8: 44.1 g/mol
no of moles= 72.3 g/44.1g/mol= 1.639 moles
moles of oxygen= 4.918 moles
grams of oxygen= 78.69 grams
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