A car is parked on a cliff overlooking the ocean on an incline that makes an ang

Question

A car is parked on a cliff overlooking the ocean on an incline that makes an angle of 15.0° below the horizontal. The negligent driver leaves the car in neutral, and the emergency brakes are defective. The car rolls from rest down the incline with a constant acceleration of 2.43 m/s2 for a distance of 35.0 m to the edge of the cliff, which is 20.0 m above the ocean. (a) Find the car's position relative to the base of the cliff when the car lands in the ocean. 24.7 Your response differs from the correct answer by more than 10%. Double check your calculations. m (b) Find the length of time the car is in the air 1.963 Your response differs from the correct answer by more than 10%. Double check your calculations. S Need Help? Read It

Explanation / Answer

Solution:-

While rolling down the incline velocity of the car

v^2 = 2aS
=>v = [2aS}^1/2
=[2*2.43 * 35]^1/2
= 13.04 m/s
Now the vertical and horizontal component of velocity
vx = v cos15 = 12.59 m/s
vy = v sin15 = -3.37 m/s
Now using the below equation
h = ho + vy * t -0.5gt^2
0 = ho + vy * t -0.5gt^2
0.5gt^2 +3.37 *t -20 = 0
Solving the above quadratic equation

.we get t = 1.71 s

1)
x = vx * t
= 12.59 m/s * 1.71s
= 21.53 m

2)
  the length of time the car is in the air =T

= 1.71

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