flip.tphysics.com FlipltPhysics Copy of Copy of Electricity & Magnetism I Univer

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flip.tphysics.com FlipltPhysics Copy of Copy of Electricity & Magnetism I Universit Homework: Magnetism Motion in a Magnetic Field 1 A charged particle of mass m . 5X10-8 kg, moving with constant velocity in the y-direction enters a region containing a constant magnetic field B 2.4T aligned with the positive z-axis as shown. The particle enters the region at (x,y)- (0.8 m, 0) andoo o leaves the region at (x,y) -0, 0.8 m a time t 475 us after it entered the region. With what speed v did the particle enter the region containing the magnetic field? What is Fx, the x-component of the force on the particle at a time t1 158.3 5 after it entered the region containing the magnetic field. 3) What is Fy, the y-component of the force on the particle at a time t,- 158.3 after it entered the region containing the magnetic field. What is q, the charge of the particle? Be sure to include the correct sign. f the velocity of the incident charged particle were doubled, how would B have to change (keeping all other parameters constant) to keep the trajectory of the particle the same? OIncrease B by a factor of 2 O Increase B by less than a factor of 2 O Decrease B by less than a factor of 2 O Decrease B by a factor of 2 O There is no change that can be made to B to keep the trajectory the

Explanation / Answer

1) velocity of the particle v = pi * r / 2 t

= pi * 0.8 / (2 * 475 * 10-6) = 2645 m/s

2) theta = pi / 6 = 0.523 rad = 30 deg

Fx = -m v2 * cos 30 / d = 5 * 10-8 * 26452 * cos 30 / 0.8

Fx = -0.378 N

3) Fy = -m v2 * sin 30 / d = 5 * 10-8 * 26452 * sin 30 / 0.8

Fy = -0.218 N

4) q = m v / B r = (5 * 10-8 * 2645) / (2.4 * 0.8)

q = -6.88 * 10-5 C

5) Increase B by a factor of 2

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