Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

o ophion (converging) lens has a focal length of 20 cn. An object, 6 cm high, is

ID: 776899 • Letter: O

Question

o ophion (converging) lens has a focal length of 20 cn. An object, 6 cm high, is located 10 cm from Athe iens. is the image Real or Virtual? Real Virtual A biconvex (converging) lens has a focal length of 20 the lens. What is the Image Height? 9) cm. An object, 6 cm high, is located 10 cm from 6 cm 6 cm 12 cm -12 cm Anob ect 6high is located 10 cm from Abicon ex (com erging, lens has a focal length of 20 cm the lens. Is the Image Upright or inverted? 10) Upright Inverted 11) A biconcave ( diverging) lens has a focal length of 20 cm. An object, 6 cm high, is located 50 cm from the lens. What is the Image Distance? 14.3 cm 14.3 cm 1000 cm 1000 cm 12) A biconcave (diverging) lens has a focal length of -20 cm. An object, 6 cm high, is located 50 cm from the lens. Is the Image Real or Virtual? Real Virtual A biconcave (diverging) lens has a focal length of -20 cm. An object, 6 cm high, is located 50 cm from the lens. What is the image Height? 13) 1.7 cm -4.3 cm 4.3 A biconcave (diverging) lens has a focal length of 20 cm. An object, 6 cm high, is located 50 cm from the lens. Is the Image Upright or Inverted? 14) Upright Inverted

Explanation / Answer

8. for converging lens

use 1/f = 1/u + 1/v

1/v = 1/20 -1/10

v = -20 cm

imgae is real

---------------

9. magnification m = h'/h = -S'/S

h' = 6cm * 20/20

h' = +6 cm

----------------------

10. +ve from abovr indicates that it is uprigt

----------------------

11. use -1/f = 1/u - 1/v

-1/20 = 1/50 -1 /v

1/v = 1/50 +1/20

v = +14.3 cm

--------------------------

12. Virtual

13. h' = 6 * -14.3/50

h' = -1.7 cm

-----------

13. inverted