1. In open heart surgery a much smaller amount of energy will defibrillate the h
ID: 776933 • Letter: 1
Question
1. In open heart surgery a much smaller amount of energy will defibrillate the heart.
(a) What voltage (in kV) is applied to the 5.00 µF capacitor of a heart defibrillator that stores 35.0 J of energy?
kV
(b) Find the amount (in mC) of stored charge.
2. Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts.
(a)What is the electric field strength (in kV/m) between them, if the potential 5.50 cm from the zero volt plate (and 4.50cm from the other) is 550 V?
kV/m
(b) What is the voltage between the plates?
V
Explanation / Answer
a) E = 1/2 C V2
V = sqrt [ 2 E / C ] = sqrt [2 * 35 / 5 * 10-6]
= 3741 V = 3.74 kV
b ) Q = C V = 5 * 10-6 * 3741
amount of stored charge = 18.7 mC
------------------------------------------------
2) a) E = V / d
= 550 / (5.5 * 10-2)
= 10,000 V/m = 10 kV/m
b) V = E d = 10,000 * 10 * 10-2
= 1000 V
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