1. Let’s say an 80 kg pole vaulter can run 10 m/s. How high can she vault? (Assu

Question

1. Let’s say an 80 kg pole vaulter can run 10 m/s. How high can she vault? (Assuming no “spring-like” action in his pole.) We are taking her kinetic energy and converting it to potential energy. (Notice, you aren't given a mass so it must cancel out.)

2. To increase ball speed, you need a higher hoop ferequency. True or false?

3. Two ways to decrease hoop frequency are... A) stretching and taping, B) rolling and shaving, or C) heating and cooling bat quickly

4.A 70 kg bungee diver is released from Verzasca Dam (Switzerland) 220 meters above the ground. The unstretched bungee cord is 150 meters long. Assume the bungee cord obeys Hooke’s law and there are no energy losses in the system.

Explanation / Answer

here,

1)

mass , m = 80 kg

intial speed , u = 10 m/s

let the height achived be h

using conservation of energy

m * g * h = 0.5 * m * u^2

9.81 * h = 0.5 * 10^2

solving for h

h = 5.1 m

the maximum height achived is 5.1 m

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