A wheel free to rotate about its axis that is not frictionless is initially at r

Question

A wheel free to rotate about its axis that is not frictionless is initially at rest. A constant external torque of +43 N m is applied to the wheel for 22 s, giving the wheel an angular velocity of +550 rev/min. The external torque is then removed, and the wheel comes to rest 120 s later. (Include the sign in your answers.) (a) Find the moment of inertia of the wheel. 12.01 kg·m,2 (b) Find the frictional torque, which is assumed to be constant. N-m You can apply Newton's second law in rotational form to both the speeding up and slowing down motions of the wheel to obtain two equations in the moment of inertia of the wheel and the frictional torque that you can solve simultaneously fo these quantities. Assume that both the speeding-up and slowing-down of the wheel took place under constant-acceleration conditions eBotk

Explanation / Answer

t-tf = I*w/t1

tf = frictional torque = I*w/t2

t = I*w/t1 + I*w/t2

t = I*w(1/t1 + 1/t2)

w = 550 rev/min = 57.6 rad/s

t = 43 N-m

t1 = 22s

t2 = 120s

I = ??

I = 13.88 kg-m^2

part b )

tf = I*w/t2

tf = 6.66 N-m

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