ve as the block moves Cour Initially, a large crate sits at the bottom of a ramp
ID: 777121 • Letter: V
Question
ve as the block moves Cour Initially, a large crate sits at the bottom of a ramp. You pull the crate up the ramp using a rope tied around the crate. a. As the crate moves up the ramp, does the gravitational force do positive work, negative work, or no work on the crate? Negative work • Positive work b. Has the gravitational potential energy of the crate increased, decreased, or remained the same as you pull it No work up the ramp? You were partially correct •U, has increased CU, has decreased CU, remained the same O Review this conce Type here to search Recognize situations potential energy of a decreases, or does not Gravitational Potential En O E Å 9 1 1Explanation / Answer
1)
a)
Word done is negative since force and displacement are in opposite directions.
b)
Gravitational potential energy increases with the height.
2)
a)
Gravitational potential energy = mgh
h is the height from the compressed state to the point where mass hit the spring.
= 0.421 x 9.8 x 0.05
= 0.20629 J
b)
Since we have taken the compressed state as the reference point, gravitational potential energy is zero.
c)
Elastic potential energy = 1/2 kx2,
Where x is the compressed distance
When the mass hit the spring, x = 0
So, elastic potential energy = 0 J
d)
Elastic potential energy, E = 1/2 kx2,
k is the spring constant, k = 1.590 N/m
x is the compressed distance, x = 0.05 m
Substituting,
E = 0.5 x 1.590 x (0.05)2
= 0.0019875 J
3)
a)
Since the reference point is the point where the mass hits the spring, potential energy there is zero.
b)
Gravitational potential energy = mgh
= 0.334 x 9.8 x ( - 0.055)
= - 0.180026 J
c)
Elastic potential energy = 0 since the spring is not compressed
d)
Elastic potential energy, E = 1/2 kx2,
k is the spring constant, k = 1.540 N/m
x is the compressed distance, x = 0.055 m
Substituting,
E = 0.5 x 1.540 x (0.055)2
= 0.00232925 J
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