An automobile tire is inflated with air originally at 10.0°c and normal atmosphe

Question

An automobile tire is inflated with air originally at 10.0°c and normal atmospheric pressure. During the process, the air is compressed to 27.0% of its original volume and the temperature is increased to 3909C (a) What is the tire pressure in pascas? 4296.46 Was this answer helpful? Use the ideal gas law to find the pressure inside the tire from its volume and temperature. Pa (b) After the car is driven at high speed, the tire's air temperature rises to 85.0°C and the tire's interior volume increases by 3.00%. what is the new tire pressure (absolute) in pascals? 4786.32 Use the ideal gas law to find the pressure of the air inside the tire from its volume and temperature. Pa Need Help? Meser to & Tuter 700s pointe Preious Answers Sercp9 10.P043 My Notes Ask Your Teacher At what temperature would the rms speed of a deuterium atom equal the following speeds? (Note: The mass of a deuterium atom is 3.320 x 1027 kg.) a) the escape speed from Earth, 1.12 x 104 m/s 1.79e4 Your response differs from the correct answer by more than 10%. Double check your calculations. K (b) the escape speed from the Moon, 2.37 x 103 m/s 4.24e3 Your response differs from the correct answer by more than 100% 2x Need Helo? Tah to itr

Explanation / Answer

(6)
(a) Initial Parameters
Temperature of the tire (T1) = 10 oC = 10+273 =283 K
Volume of the tire say V1
Pressure of the tire (P1) = 1atm = 101.324 kPa
Now the final temperature is T2 = 39 oC = 39+273 = 312 K
Final volume (V2) = 0.27V1
Now we know that from ideal gas
PV = nRT
PV/T = nR = C . therefore
P1V1 / T1 = P2V2 / T2
(101.3*103)V1 / (283) = P2*(0.27V1) / 312
P2 = (101.3*103)*(312/283)*(1/0.27)
P2 = 4.136*105 Pa
(b) In this case temperature is (T3) = 85 oC = 85+273 = 358 K
Volume (V3) = 1.03V2 = 1.03*(0.27)V1 = 0.2781V1
Applying the same law
P1V1 / T1 = P3V3 / T3
(101.3*103)V1 / (283) = P3*(0.2781V1) / 358
P3 = (101.3*103)*(358/283)*(1/0.2781)
P3 = 4.61*105 Pa
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