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T-Mobile LTE 1:03 AM O 5896 usu34ny.theexpertta.com C Assign 7 Begin Date: 3/14/

ID: 777757 • Letter: T

Question

T-Mobile LTE 1:03 AM O 5896 usu34ny.theexpertta.com C Assign 7 Begin Date: 3/14/2018 11:00:00 AM -Due Date: 3/19/2018 9:00:00 AM End Date: 3/19/201 9:00:00 AM (25 %, Probem 2: Two black. whch a. be madeled a. put mana, are connoctied by a masslcs string which passcs through a holc in a frictionless table. A tube estands out of the hole in the table so that the potion of the string between the hole and MI nemains parallel to the top of the table. The blocks have mas fictioeless serface. Block 2 hangs veically undermeat 50% Part (a) Assume that block two, M2. does not move relative to the table and that block one, Mi, is rotating around the table. What is the speed of block one, Mi. in meters per second? 50% Part (b) How much time, in seconds, does it take for block one, MI, to make one revolution? All content 6 2018 Expent TA., LLc

Explanation / Answer

a)

For the hanging block to stay stationary, its weight must provide the centripetal force of the spinning block.
m2 * g = m1 * v^2 / r

2.3kg*9.8 = 1.3 kg*v2 / 0.75

v2 = 16.905 / 1.3
v = 3.61 m/s

b)

Time of revolution = 2r * pi / v = 2*0.75*(3.141/3.61) = 1.30 s