1.Find the electric field intensity in volts per meter between the plates of the

Question

1.Find the electric field intensity in volts per meter between the plates of the capacitor if the separation distance is 0.50 mm. (Hint: How is the magnitude of the electric field intensity related to the potential difference between two points separated by a known distance?)

2.To one decimal place, what is the voltage in volts across the 2.0 kilo-ohm resistor when the capacitor is fully charged?

3.To the nearest tenth of a milliamp, what is the current at the instant that the discharging of a fully charged capacitor begins, at t = 0? That is, at the instant the knife blade is thrown the other way and point d is connected to point b.

4.To the nearest tenth of a milliamp, what is the current at t = 1.00 second?

5. Find the equivalent capacitance in micro-farads of the connection of the two capacitors when another capacitor of 3000 micro-farad is connected in series with the 1500 micro-farad capacitor.

6. Remove the 3000 micro-farad capacitor from the system. Find the equivalent capacitance in micro-farads of the connection of the two capacitors when the 3000 micro-farad capacitor is connected in parallel with the 1500 micro-farad capacitor.

7. To the nearest tenth of a millijoule, how much energy is stored in the 1500 microfarad and 3000 microfarad capacitors when they are connected in series?

8.To the nearest tenth of a millijoule, how much energy is stored in the 1500 microfarad and 3000 microfarad capacitors when they are connected in parallel?

Please show any work that you can. Thanks so much! (:

Explanation / Answer

1) E = V/d = 3 / 5e-4 = 6000 V/m

2) As the capacitor is fully charged, the current stops flowing in the circuit, it means voltage drop across the resistor is zero.

3) The current will be same at t=0 as given by V= I*R

4) not sure about this one

5) for capacitor in series,

1/cequ = 1/c1 + 1/c2 = 1/3000 + 1/1500

cequ = 1000 micro farads

6) for parallel, just add

cequ = 3000 + 1500 = 4500 micro farads.

7) energy stored = 1/2*C*V2

for series, E = 1/2*1000*9 = 4500 joules

8) for parallel, E = 1/2*4500*9 = 20250 joules

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