(3%) Problem 20: Analysis of the interference effect in a transparent solid show

Question

(3%) Problem 20: Analysis of the interference effect in a transparent solid shows that the wavelength of the laser passing through the solid is 329 nm inside the solid nMedium Gasses at 0°C. 1 atm Solids at 20C 2.419 1.434 1.52 1.66 1.309 1.49 ir 1.000293 Diamond Carbon dioxide 100045 Fluorite Hydrogen Oxygen 1.000139 Glass, crown 1.000271 Glass, flint Liquids at 20O Ice at 0°C Polystyrene Benzene .501 Carbon disulfide .628Sodium chloride 1.544 Carbon tetrachloride 1.461 Quartz, crystalline 1.544 Ethanol Water, fresh Glycerine 1.361 Quartz, fused 1.458 1.333Zircon 1.473 1.923 Otheexpertta.com 50% Part (a) Knowing this light comes from a He-Ne laser and has a wavelength of 633 nm in air, what is the index of refraction of the substance? Grade Summary Deductions Potential 0% 100% sinO cotan) asin) tan)J( acos) Submissions Attempts remaining: 2 (2% per attempt) detailed view cosO atan)acotan)sinh( coshO tanhO cotanhO Degrees O Radians 0 END Submit Hint I give up! Hints: 0% deduction per hint. Hi ints remaining: 2 Feedback: deduction per feedback. Submission History Answer Hints Feedback Totals Totals 0% 0% 0% 0% 50%. Part (b) What is the likely substance?

Explanation / Answer

we know that

n, refractive index = o(wavelength of light in vaccum) / (wavelength of light in given medium)

we have wavelength of given light in air = 633nm

and from table we know refractive index of air = 1.000293

thus

1.000293 = 0 / 633nm

0 = 1.000293 * 633e-9 ~ 633e-9

now wavelength of given light in medium given = 329 nm

thus n = 633e-9 / 329e-9 = 1.924

part b) The element is Zircon

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