If the solubility-product constant of lead(II) iodide at 25 o C is 7.1 x 10 -9 t

Question

If the solubility-product constant of lead(II) iodide at 25oC is 7.1 x 10-9 to which expression does this value correspond?

A. [Pbl2] [Pb2+]-1 [I-]-2

B.  [Pb2+]-1[I-]-2

C.   [Pb+] [I-]2

D.  [Pb2+] [I-]2

Given the Ksp of lead(II) iodide is 7.1 x 10-9 at 25oC, which is its molar solubility at 25oC?

A. 1.21 x 10-3 M

B. 8.43 x 10-6 M

C. 1.92 x 10-3 M

D. 4.81 x 10-4 M

A. [Pbl2] [Pb2+]-1 [I-]-2

B.  [Pb2+]-1[I-]-2

C.   [Pb+] [I-]2

D.  [Pb2+] [I-]2

Given the Ksp of lead(II) iodide is 7.1 x 10-9 at 25oC, which is its molar solubility at 25oC?

Answer

A. 1.21 x 10-3 M

B. 8.43 x 10-6 M

C. 1.92 x 10-3 M

D. 4.81 x 10-4 M

Explanation / Answer

D.  [Pb2+] [I-]2

7.1 x 10-9 = 4s^3

(7.1*10^-9/4)^(1/3)

s = 1.21 * 10^-3

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