1.) You carefully weigh out 20.00g of CaCO3 powder and add it to 81.00g of HCl s

Question

1.) You carefully weigh out 20.00g of CaCO3 powder and add it to 81.00g of HCl solution. You notice bubbles as areaction takes place. You then weigh the resulting solution and find that it has a mass of 92.80g. The relevant equation is

CaCO3(s)+2HCl-->H2O(l)+CO2(g)+CaCl2(aq). Assuming no other reactions take place, what mass of CO2 was produced.

Answer should be three sig figs and include the appropiate unit.

Thank You!!!!

2.) Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)--->2AlCl3(s)

Answer should be three sig figs and include appropiate unit.

Thank You!!!!

Explanation / Answer

20g CaCO3

81g HCl sol

92.8g CaCl2 + H2O +impurities.

So, 101-92.8 = 8.2g CO2 is formed.

------------------------------

Al ---> 27/27 = 1 mol

Cl ---> 32/35.45 = 0.903 mol

In excess Cl2, we would have 2/2 = 1 mol AlCl3

In excess Al, we would have: 2/3*0.903 = 0.602 mol AlCl3

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