If 0.720 m o l of a nonvolatile nonelectrolyte are dissolved in 3.90 m o l of wa

Question

If 0.720mol  of a nonvolatile nonelectrolyte are dissolved in 3.90mol of water, what is the vapor pressure PH2O of the resulting solution? The vapor pressure of pure water is23.8 torr at 25 %u2218C . Express your answer numerically in torr.
Please explain!! If 0.720mol  of a nonvolatile nonelectrolyte are dissolved in 3.90mol of water, what is the vapor pressure PH2O of the resulting solution? The vapor pressure of pure water is23.8 torr at 25 %u2218C . Express your answer numerically in torr.
Please explain!!

Explanation / Answer

Xsolvent = 0.72 mol / (0.72 mol + 3.90 mol)

Xsolvent = 0.1558

Xsolute(H2o) = 0.8442

Psolute(H2o)  = 0.8442 x 23.8 = 20.09196 torr

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