For estimating ozon in the air, a certain volume of air is passed through an aci

Question

For estimating ozon in the air, a certain volume of air is passed through an acidified or neutral KI solution when oxygen is evovled and iodide is oxidized to give iodine. when such a solution is acidified , free iodine is evolved which can be titrated with standard Na2S2O3 solution. in an experiment 10 litre of air at 1 atm and 27*c were passed through an alkaline KI solution , at the end the iodine entrapped in a solution an titration as above required 1.5 mL of 0.01 N Na2S2O3 solution. calculate volume % of O3 in sample.

Explanation / Answer

solution : the reaction are H2O +2KI +O3 -----> 2KOH +I2+O2 here also 2e+I2 ------> 2I` 2(S^(+2))2 ------> (S^(5/2+) + 2e Meq. of I2 = Meq. of Ns2S2O3 = 1.5x0.01= 1.510^(-2) mM of I2 = 1.5x10^(-2)/2 = 7.5x10^(-3) mM of O3= mM of I2 = 7.5x10^(-3) P`o3 = nRT/V = [7.5x10^(-3)x0.0821x300] / 10 = 184.72x10^(-7) atm vol % of O3 = 184.72x10^(-7)x100 = 1.847x10^(-3) %

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