What is the minimum amount of 6.4 M H 2 S O 4 necessary to produce 24.4 g of H 2

Question

What is the minimum amount of 6.4M H2SO4 necessary to produce 24.4g of H2 (g) according to the following reaction? 2Al(s)+3H2SO4(aq)%u2192Al2(SO4)3(aq)+3H2(g) Express your answer using two significant figures.
Please explain how to figur this out Thank you in Advance!! What is the minimum amount of 6.4M H2SO4 necessary to produce 24.4g of H2 (g) according to the following reaction? 2Al(s)+3H2SO4(aq)%u2192Al2(SO4)3(aq)+3H2(g) Express your answer using two significant figures.
Please explain how to figur this out Thank you in Advance!!

Explanation / Answer

2Al(s)   +   3H2SO4(aq) ------------> Al2(SO4)3(aq) +   3H2(g)

moles of H2 = 24.4/2 = 12.2 moles

so 3 moles of H2 are given by 3 moles of H2SO4

so moles of H2SO4 = 12.2 moles

so moles = conc*volume

volume = 12.2/6.4 = 1.90625 L = 1.91 L................ans

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