Calculate the concentration of all ions present in each of the following solutio

Question

Calculate the concentration of all ions present in each of the following solutions of strong electrolytes.(a) 0.0214 mol of sodium phosphate in 10.5 mL of solutionchemical concentration Mcation concentration Manion concentration M(b) 0.348 mol of barium nitrate in 630.0 mL of solutionchemical concentration Mcation concentration Manion concentration M(c) 1.47 g of potassium chloride in 0.525 L of solutionchemical concentration Mcation concentration Manion concentration M(d) 114 g of ammonium sulfate in 1.30 L of solutionchemical concentration Mcation concentration Manion concentration M

Explanation / Answer

(a) 0.0214 mol of sodium phosphate in 10.5 mL

Na3PO4 ---------> 3 Na+ + PO43-

0.0214 3*0.0214 0.0214

so conc

[Na+] = 3*0.0214/0.0105 = 6.11 M

[PO4 3-] = 2.038 M

(b) 0.348 mol of barium nitrate in 630.0 mL

Ba(NO3)2 -----> Ba2+ + 2 NO3-

0.348 0.348 2*0.348

[Ba2+] = 0.348/0.63 = 0.55 M

[NO3-] = 1.105 M

(c) 1.47 g of potassium chloride in 0.525 L

moles = 1.47/74.55 = 0.0197

KCl ----> K+ + Cl-

0.0197 0.0197 0.0197

[K+] = 0.0197/0.525 = 0.0375 M = [Cl-]

(d) 114 g of ammonium sulfate in 1.30 L of solution

moles of ammonium sulfate = 114/132.14 = 0.863 moles

NH4)2 SO4 -----> 2NH4+ + SO4 2-

0.863 2*0.863 0.863

[NH4+] = 2*0.863/1.3 = 1.327 M

[SO4 2-] = 0.664 M

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