The Fischer-Tropsch process is a reaction in which a mixture of carbon monoxide
ID: 784820 • Letter: T
Question
The Fischer-Tropsch process is a reaction in which a mixture of carbon monoxide and hydrogen gas react to form hydrocarbons. The length of the hydrocarbon chain is dependent on pressure and temperature, but the reaction is not very selective and often multiple product hydrocarbons form. Carbon monoxide and hydrogen gas are fed into a reactor at 250.0
The Fischer-Tropsch process is a reaction in which a mixture of carbon monoxide and hydrogen gas react to form hydrocarbons. The length of the hydrocarbon chain is dependent on pressure and temperature, but the reaction is not very selective and often multiple product hydrocarbons form. Carbon monoxide and hydrogen gas are fed into a reactor at 250.0ºC and 1 atm. The product gas exits at 250.0ºC, 1 atm and contains 10.1 mol/hr of n-butane (C4H10), 24.1 mol/hr of n-pentane (C5H12), water vapor, and unreacted carbon monoxide and hydrogen gas. Only 90.0 % of the incoming carbon monoxide gas and 72.0% of the incoming hydrogen gas react. The Fischer-Tropsch reactions and process flow diagram are below. 9H2 + 4CO ? C4H10 + 4H2O 11H2 + 5CO ? C5H12 + 5H2O What is the molar flow rate of carbon monoxide into the reactor? What is the molar flow rate of hydrogen gas into the reactor? What is the molar flow rate of carbon monoxide gas out of the reactor? What is the molar flow rate of hydrogen gas out of the reactor? What is the flow rate of water gas out of the reactor?Explanation / Answer
per hour butane moles = 10.1 , propane moles = 24.1 ,
4CO + 9H2 -----> C4H10 + 4H2O
5CO +11H2 --> C5H12 + 5H2O,
since butane moles 10.1 , CO moles = 4(10.1) = 40.4 ,
since propane moles = 24.1 , CO moles = 24.1x5 = 120.5
total CO moles per hour = 120.5+40.4 = 160.9
since process is 90 % effecient , CO moles requird = (160.9 x100/90)
= 178.78 , flow rate = 178.78 mol/hr
b) H2 = (9x10.1 + 11x24.1)/0.9 = 395.55 mol/hr
c) 10% CO flows , (10x178.78/100) = 17.78 mol/hr
d) 10% H2 = 395.55x10/100 = 39.55 mol/hr
e) H2O moles = (4x10.1+ 24.1x5) = 160.9 mol/hr
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