1.) ItIt is desired to make 1.00 L of 1.34 M NaNO2 from a more concentrated 5.48

Question

1.)  ItIt  is desired to make 1.00 L of 1.34 M NaNO2 from a more concentrated 5.48 M NaNO2.

a.     How many moles of NaNO2 will be contained in the 1 liteer, 1.34 solution after it is made?

b.     What volume of concentrated 5.48 M NaNO2 solution will contain this number of moles?

c.      If this volume of concentration NaNO2 (answer to b) is diluted to 1 liter, what will be the molarity of the solution?

ItIt is desired to make 1.00 L of 1.34 M NaNO2 from a more concentrated 5.48 M NaNO2. How many moles of NaNO2 will be contained in the 1 liteer, 1.34 solution after it is made? What volume of concentrated 5.48 M NaNO2 solution will contain this number of moles? If this volume of concentration NaNO2 (answer to b) is diluted to 1 liter, what will be the molarity of the solution?

Explanation / Answer

a)1.34=n/1=1.34moles

b)5.48=1.34/v

=>v=0.244L

C)M=n/L

=1.34/1=1.34M

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