If the hydrogen chloride gas produced above is trapped in 250.0 mL of water, wha

Question

If the hydrogen chloride gas produced above is trapped in 250.0 mL of water, what would be the molarity of the solution?

How many milliliters of a 0.350 M magnesium hydroxide solution are needed to neutralize the hydrochloric acid solution in the question above?

If the hydrogen chloride gas produced above is trapped in 250.0 mL of water, what would be the molarity of the solution? How many milliliters of a 0.350 M magnesium hydroxide solution are needed to neutralize the hydrochloric acid solution in the question above?

Explanation / Answer

in above equation considering 1 mol of HCl (g) is produced

molarity in 250 ml water = moles of HCl/ volume of water = 1/.25 = 4M

MgOH + 2HCl -----> MgCl2 + H2O

for 1 mole of HCl >>>> .5 moles of MgOH is required to neutralize

thus .35 = .5/volume >>>>>> V= (.5/.35)*1000 mL = 1428.57 mL

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