The aminoacid glycine is often used as the main ingredient of a buffer in bioche

Question

The aminoacid glycine is often used as the main ingredient of a buffer in biochemical experiments.

The amino group of glycine, which has a pKa of 9.6, can exist either in the protonated form ( -NH3+) or as the free base (-NH2), because of the reversible equilibrium

R-NH3+ <->R-NH2 + H+

How much of 5 M NaOH must be added to 1 L of 0.1 M glycine at pH 9.0 to bring its pH to

exactly 10.0?

The part I'm stuck on is when you solve it out and have 0.25119 = (0.1-x)/x  

How do you solve for x in this situation?

Explanation / Answer

0.25119 = (0.1-x)/x

then 0.25119x = 0.1-x,

x = 0.1/1.25119 = 0.08

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