In a reaction between pure acetic acid and sodium bicarbonate, 15.2 grams of sod

Question

In a reaction between pure acetic acid and sodium bicarbonate, 15.2 grams of sodium bicarbonate was added to 21.0 mL of acetic acid. Which reactant is the limiting reactant in this reaction?

Name of limiting reactant (acetic acid or sodium bicarbonate):

How many moles of the limiting reactant are present in this reaction?

Moles of limiting reactant = mol

How many moles of carbon dioxide do you expect to be produced?

Moles of carbon dioxide = mol CO2

If the temperature in the laboratory is 24.4 oC and the atmospheric pressure is 0.918 atm, what volume would be occupied by the carbon dioxide produced in this reaction (in cm3)?

Volume of carbon dioxide = cm3

What would be the circumference of a spherical balloon containing this amount of carbon dioxide gas?

Circumference of balloon = cm

Explanation / Answer

acetic acid mass = vol x desity = 21 x 1.05 = 22.05 , moles = 22.05/60 = 0.3672

sodium bicarbonate moles = 15.2/84 = 0.181 ,

acetic acid and sodium carbonate react in 1: 1 ratio

CH3COOH + NaHCO3 ------> CH3COONa + H2O + CO2 ,

hence sodium carbonate being less in moles reacts wcompletly ,

thus sodium bicarbonate is limiting reagent

moles of limiting reactnst = 0.181,

CO2 moles = 0.181,

V = nRT/P = 0.181 x0.0821x (273+24.4)/0.918    = 4.814 liters = 4814 cm3

V = (4/3)3.14 r^3 = 4814

r = 10.477 cm

circumference 2pi r = 2 x3.14 x10.477 = 65.8 cm

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