Copper(2) chloride (Cucl2) was dissolved in water and piece of aluminum wire (Al

Question

Copper(2) chloride (Cucl2) was dissolved in water and piece of aluminum wire (Al; 0,56g) was placed in the solution. The blue color due to copper (2) chloride soon faded and a red precipitate of solid copper was observed. After the blue color had dissapeared completely? the leftover aluminum wire was removed from the solution and weighted. The mass of the leftover aluminum wire was 0,43g.

1. Calculate the numer of moles of (a) copper (2) aand (b) aluminum that reacted

2.What is the mole ration of copper (2) chloride to aluminum metal? Express this to the nearest whole number ratio.

3. What happened to the aluminum metal that was consumed in this reaction. Write the formula of the most probable aluminum-containing product.

4. Write a balanced chemical equcation for the single replacement reaction of cooper(2) chloride with aluminum.

Explanation / Answer

Q3 Aluminium metal gets converted into AlCl3

Q4 2Al (s) + 3CuCl2(l)-----> 2AlCl3(l)+ 3Cu(s)

Q1 Moles of Al reacted = (.56-.43)/26.98=.13/26.98 =.00482, Moles of CuCl2 reacted = .00482x3/2 =.00727

Q2 Molar ratio of CuC2 : Al = 3 :2

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