1) The octane rating of gasoline is a relationship of the burning efficiency of

Question

1) The octane rating of gasoline is a relationship of the burning efficiency of the given gasoline mixture to the burning efficiency of octane (C8H18). like most hydrocarbons, octane reacts with oxygen gas to produce carbon dioxide and water. The unbalanced equation for this reaction is C8H18(g) + O2(g)--->CO2(g) +H2O(g)
Balanced chemical equation 2 C8H18(g) + 25 O2(g) --->16 CO2(g) + 18 H2O(g)

Question 1: how many moles of water are produced in this reaction?
H20 produced = ???????? moles

Question 2: after the reaction, how much octane is left ? express your answer in moles.
moles of C8H18 remaining = ?????

2) The Haber-Bosch process is a very important industrial process. In the Haber-Bosch process, hydrogen gas reacts with nitrogen gas to produce ammonia according to the equation 3H2(g)+N2(g)--->2NH3(g)
The ammonia produced in the Haber-Bosch process has a wide range of uses, from fertilizer to pharmaceuticals. However, the production of ammonia is difficult, resulting in lower yields than those predicted from the chemical equation.

1.46g H2 is allowed to react with 9.56g N2, producing 1.31g NH3

Question 1: What is the theoretical yield for this reaction under the given conditions? Express your answer numerically in grams

Question 2: What is the percent yield for this reaction under the given conditions? Express the percentage numerically.

Explanation / Answer

1) data not given

2) mol of H2 = 1.46/2 = 0.73, N2 mol = 9.56/28 = 0.3414 ,

limiting reagent is H2 while N2 is ecxess reagent ,

mol of NH3 = ( 2/3)(0.73) = 0.4866

NH3 mass = 0.4866 x17 = 8.273 gm is theoretical yield

% yiedld = ( 1.31/8.273) x100 = 15.835 %

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