The following date was collected from the experiment: 1] weight of the test tube

Question

The following date was collected from the experiment:

1] weight of the test tube + KClO3 + MnO2=  23.09g

2] weight of the test tube + contents after reaction=  23.08g

3] weight of oxygen produced=  .01g

4] temperature of water=  22.1 degrees Celsius

5] volume of water= 10mL= volume of O2 gas 10mL

6] barometric pressure= 756.92 mm Hg

7] vapor pressure of water= 19.827 mm Hg

Find the following:

(1) Pressure of O2 gas (show calculations)

(2) Gas-law constant, R, from ideal-gas law (show calculations)

(3) R from the van der Waals equation (show calculatiosn)

(4) Accepted value of R_____ (Source of R value)

(5) Uncertainity in R (show calculations)

Explanation / Answer

a) Vapour pressure of water = 19.827 mm Hg

Pressure of O2 gas = (0.01 /32)* (756.92+19.927) = 77.6/32 = 2.425 mm Hg

2) PV = n *R *T

R = 0.0003*10 * *(295.1)/(10^-2) = 8.214 J K ^-1 mol ^-1

3)R value from the vanderwaals equation

(P+a/V^2)*(V- n*b) = n *R *T

R = (P+a/V^2) (V- n *b) /nT = (2.425 )( 10 - 39.4*10^-6 *0.01/32) /(0.01/32)*(395.1K)

R = 8.3 J k^-1 mol ^-1

4) Accepted value of R =8.314 J K^-1 mol^-1

5) Uncertanity in R using ideal gas eqn = 8.314-8.214/8.314 *(100%) = 1.2%

Uncetanity in R using vanderwaals eqn = 8.314 - 8.3/8.314 *(100%) = 0.168 %

This is true because in reality ideal gas deviate a large extent from "IDEAL GAS EQUATION" which while the deviation is less for "VANDERWAALS EQUATION" because it takes into account some of the real gas characteristics .

But till date no gas equation was able to desribe the behaviour of an ideal gas perfectly

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.