Here are three different methods of expressing the van\'t Hoff factor: i = appar

Question

Here are three different methods of expressing the van't Hoff factor:

i = apparent mole of particles to solution/moles of solute

i = apparent particle concentration/solute concentration

i = observed colligative property/ collegative property asuming no dissociation

i=observed colligative property colligative property assuming no dissociation

At what temperature would a 1.70m NaCl solution freeze, given that the van't Hoff factor for NaCl is 1.9? K for water is 1.86 degrees C/m? A 0.050 M solution of had an observed osmotic pressure of 3.85 atm at 20 degrees C. Calculate the Van't Hoff factor i for AlCl3 Here are three different methods of expressing the van't Hoff factor: i = apparent mole of particles to solution/moles of solute i = apparent particle concentration/solute concentration i = observed colligative property/ collegative property asuming no dissociation

Explanation / Answer

Part A:

When a solute is dissolved in a solvent, the freezing point of a solution is lowered according to the equation:

?T = i

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