Question#1: Question#2: Question #3: Calculate the final volume (L) of a 0.0783

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Question#1:

Question#2:

Question #3:

Calculate the final volume (L) of a 0.0783 mol/L solution prepared by diluting 20.8 mL of 0.155 mol/L lithium carbonate with water. Write a balanced equation for the following skeleton equation by inserting the correct coefficients (if a coefficient = 1, enter "1" in the provided box): The mineral galena is composed of lead(II) sulfide and has an average density of 7.46 g/cm3. What amount (mol) of lead(II) sulfide is in 20.41 m3 of galena? (Enter your answer in scientific notation.) How many lead atoms arc in 7.86 dm3 of galena? atoms of Pb (Enter your answer in scientific notation.)

Explanation / Answer

1) V = 20.8*.155/.0783 = 41.175 ml

2) coefficients are 1 4 1 2 respectively.

3) wt = 20.41*10^6 * 7.46 = 152.258 *10^6 gm

no.of moles = wt / MW = 152.258/(207+32) * 10 ^6 = 6.3* 10^5 moles

b) wt = 7.86* 10^3 * 7.46 = 58.635 * 10^3 g

no.of atoms of Pb = 58.635*1000/207 * 6.023*10^23 = 1.07 * 10^26 atoms

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