Gaseous methane will react with gaseous oxygen to produce gaseous carbon dioxide

Question

Gaseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 10.7 g of methane is mixed with 41. g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction.
Round your answer to significant digits. Gaseous methane (CH4) will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO2)and gaseous water (H2O). Suppose 10.7 g of methane is mixed with 41. g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction.

Explanation / Answer

CH4+2O2---->CO2+2H2O

From the reaction it is clear that 1 mole CH4 reacts with 2 moles O2 to produce 1 mole CO2 and 2 moles H2O

10.7g Methane=10.7/16=0.66875 moles

41 g O2=41/32=1.28125 moles

Hence O2 is the limiting reagent and reacts with (1.28125/2)=0.640625 moles CH4 to produce 1.28125 moles H2O

So mass of H2O=1.28125x18

=23.06 g

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