The 13C nucleus is a spin 1/2 particle, which means it can orient in two directi
ID: 789415 • Letter: T
Question
The 13C nucleus is a spin 1/2 particle, which means it can orient in two directions in a magnetic field
(with the field and against it). The difference in energy between the two orientations is given by:
dE = (0.705 x 10^-26 J T^-1)B
where B is the magnetic field strength in Tesla. In an NMR spectrometer with a 1.45 T field strength,
what is the ratio of the population of nuclei oriented opposite the magnetic field with respect to those
oriented with the magnetic field at 25 C?
Explanation / Answer
population of higher energy spin level
n1/N = exp( -E/RT)
where E = 0.705 x10^-26 x 1.45 = 1.022 x10^-26 J
n1/N = exp( -1.022 x10^-26 /8.314 x298) = 1
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