Using the data given below at 25C, calculate the change in enthalpy (?H) for the

Question

Using the data given below at 25C, calculate the change in enthalpy (?H) for the following reaction:


2PCl3(g)  +  O2(g) --> 2POCl3(g)



Species: O2(g), PCl3(g), POCl3(g),

?Hof kJ/mol: 0,   -288.07,   -542.2,  PLEASE EXPLAIN
Question options: -508.26 kJ -830.27 kJ 830.27 kJ Using the data given below at 25C, calculate the change in enthalpy (?H) for the following reaction:


2PCl3(g)  +  O2(g) --> 2POCl3(g)



Species: O2(g), PCl3(g), POCl3(g),

?Hof kJ/mol: 0,   -288.07,   -542.2,  PLEASE EXPLAIN
Using the data given below at 25C, calculate the change in enthalpy (?H) for the following reaction:


2PCl3(g)  +  O2(g) --> 2POCl3(g)



Species: O2(g), PCl3(g), POCl3(g),

?Hof kJ/mol: 0,   -288.07,   -542.2,  PLEASE EXPLAIN
-508.26 kJ -830.27 kJ 830.27 kJ -508.26 kJ -830.27 kJ 830.27 kJ -508.26 kJ -830.27 kJ 830.27 kJ

Explanation / Answer

The answer is: -508.26 kJ


2 PCl3(g) + O2(g) => 2 POCl3(g)

Delta H = Delta Hf(products) - Delta Hf(reactants)

= 2 x Delta Hf(POCl3) - 2 x Delta Hf(PCl3) - Delta Hf(O2)

= 2 x (-542.2) - 2 x (-288.07) - 0

= -508.26 kJ

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