Write a complete ionic equation to show the reaction of aqueous lead ( I I ) nit

Question

Write a complete ionic equation to show the reaction of aqueous lead(II) nitrate with aqueous potassium sulfate to form solid lead(II) sulfate and aqueous potassium nitrate. Express your answer as a chemical equation. Identify all of the phases in your answer. Write a complete ionic equation to show the reaction of aqueous lead(II) nitrate with aqueous potassium sulfate to form solid lead(II) sulfate and aqueous potassium nitrate. Express your answer as a chemical equation. Identify all of the phases in your answer.

Explanation / Answer

(aq) means aqueous solution
(s) means solid (sometimes called a precipitate)
(g) is gas phase
(l) is liquid phase


molecular equation (balanced)

Pb(NO3)2(aq) + K2SO4(aq) ---------> PbSO4(s) + 2KNO3(aq)

compounds with (aq) beside them are dissociated into their constituent ions in water.
Write out the TOTAL IONIC equation by showing each (aq) compound as its ions

Pb^2+(aq) + 2NO3^-(aq) + 2K^+(aq) + SO4^2-(aq) ------> PbSO4(s) + 2K+(aq) + 2NO3^-(aq)

You can see that there are 2K+(aq) and 2NO3^-(aq) on each side of the arrow. These two species have not changed at all the reaction (they are the same charge and in the same state on both sides of the arrow). They are called spectator ions, because they do not participate in the reaction.

The spectator ions cancel out, and you write the
NET IONIC equation without the spectator ions

Pb^2+(aq) + SO4^2-(aq) -----------> PbSO4(s)

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