a green Allien monster mates with a red A green alien monster mates with a red a

Question

a green Allien monster mates with a red A green alien monster mates with a red alien monster. All of their horrible spawn are green. The spawn then undergo self-fertilization. When the spawn self-fertilize, 3/4 of their offspring are green and 1/4 are red. Based on this information, answer the following questions: 1) Which alien color is dominant? _____ 2) What are the genotypes of the F_ aliens? _____and _____ 3) What is the phenotype of the F_ aliens? ____ 4) What is the genotypic ratio of the F_ aliens? _____ 5) Are the green F_ aliens homozygous or heterozygous? _____6) Are the red F_, aliens homozygous or heterozygous? ______7) Is it possible for an alien to be a carrier of the green allele? ______ 8) Draw Punnett squares illustrating the breeding results described above for the F_1 and F_1 generations. Be sure to indicate which square is for the F_1 generation and which is the F_2.

Explanation / Answer

Please find the answers below:

Part 1: Since 75% of the progeny after self-cross is green in color, the allele for green color is dominant in nature.

Part 2: It can be ascertained from the information that the F1 progeny contains all organisms as green in color. Further, when these F1 progeny are selfed, they give green:red in 3:1 ratio. This clearly can be possible only if the parents are true breeding for their traits i.e. green (GG) and red (gg).

Part 3: As given in the information, the phenotype of all the offsprings in F1 is green.

Part 4: As 3/4 offsprings are green and 1/4 offsprings are red, the phenotypic ratio will be green : red :: 3:1

Part 5: According to the information, the genotypes of the F2 population should be given as RR:Rr:rr :: 1:2:1

Part 6: All the F1 organisms will be heterozygous in nature since their parents are true breeding for their traits.

Part 7: No. Since green color phenotype is dominant in nature, an alien cannot be carrier for it. If an alien carries allele for green color even in heterozygous condition, it will be always expressed.

Punnett square:

Parents: GG * gg

F1 phenotype: All green

F1 genotype: All Gg

For F2 population, F1 offsprings underwent selfing:

Gg * Gg

F2 phenotype: Green : red :: 3: 1 (i.e. 3/4 : 1/4)

F2 genotype: GG: Gg: gg :: 1:2:1

G G g Gg Gg g Gg Gg

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