Two different substances at different temperatures are allowed to come in contac

Question

Two different substances at different temperatures are allowed to come in contact and thermally equilibrate. The mass of the first substance "A" is 31.00 g and its inital temperature is 21.4 degree cellsius. Substance "A" is allowed to come into contact with substance "B". Substance "B" has a mass of 46.28 g and its inital temperature is 86.5 degrees celsius. These two substances reach thermal equilibrium at a temperature of 64.2 degree celsius. If the specific heat capacity of substance "B" is 1.17 J / g-C, what is the specific heat of substance "A". (assume no heat is lost to the surroundings)

Explanation / Answer

heat lost by B = heat gained by A

mass x specific heat x temp change for B = mass x specifc heat x temp change for A

46.28 x 1.17 x ( 86.5-64.2) = 31 x ( 64.2-21.4) x S

Speciifc heat of A = S = 0.91 J/g-C

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