Calculate the pH of each of the following strong acid solutions. (a) 0.00302 M H

Question

Calculate the pH of each of the following strong acid solutions. (a) 0.00302 M HIO4 (b) 0.544 g of HIO4 in 16.0 L of solution (c) 66.0 mL of 8.40 M H2SO4 diluted to 3.60 L (d) a mixture formed by adding 89.0 mL of 0.00230 M HIO4 to 56.0 mL of 0.00671 M H2SO4 Calculate the pH of each of the following strong acid solutions. Calculate the pH of each of the following strong acid solutions. Calculate the pH of each of the following strong acid solutions. Calculate the pH of each of the following strong acid solutions. (a) 0.00302 M HIO4 (a) 0.00302 M HIO4 (a) 0.00302 M HIO4 (a) 0.00302 M HIO4 (b) 0.544 g of HIO4 in 16.0 L of solution (b) 0.544 g of HIO4 in 16.0 L of solution (b) 0.544 g of HIO4 in 16.0 L of solution (b) 0.544 g of HIO4 in 16.0 L of solution (c) 66.0 mL of 8.40 M H2SO4 diluted to 3.60 L (c) 66.0 mL of 8.40 M H2SO4 diluted to 3.60 L (c) 66.0 mL of 8.40 M H2SO4 diluted to 3.60 L (c) 66.0 mL of 8.40 M H2SO4 diluted to 3.60 L (d) a mixture formed by adding 89.0 mL of 0.00230 M HIO4 to 56.0 mL of 0.00671 M H2SO4 (d) a mixture formed by adding 89.0 mL of 0.00230 M HIO4 to 56.0 mL of 0.00671 M H2SO4 (d) a mixture formed by adding 89.0 mL of 0.00230 M HIO4 to 56.0 mL of 0.00671 M H2SO4 (d) a mixture formed by adding 89.0 mL of 0.00230 M HIO4 to 56.0 mL of 0.00671 M H2SO4

Explanation / Answer

a. pH = -log(H)

-log(0.00302)= 2.51 M

b. H: 1 gm/mol

I: 126.9 gm/mol

O: 16 x 4 = 64 gm/mol

1 + 126.9 + 64 = 191.9 mol^-1 x gm

convert 0.544 of HIO4

0.544 gm (1mole/191.9 gm) = 0.0028 = 2.8 x 10^-3 mol

concentration of HIO4

2.8 x 10^-3mol/16L = 0.0448 = 4.5 x 10^-2 mol/liter

pH = -log(4.5 x 10^-2 mol/liter) = 1.66

c.   MconcVconc = MdilVdil and solve for Mdil

Vconc = 66.0 mL x (1 liter/1000mL)

Vdil

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