Volume of HCL=50 Molarity HCL = 2.199 Volume of NaOH = 54 Molarity of NaOH= 2 In
ID: 793956 • Letter: V
Question
Volume of HCL=50
Molarity HCL = 2.199
Volume of NaOH = 54
Molarity of NaOH= 2
Initial temperature of HCL = 23C
Initial temperature of NaOH= 23.2C
1). Heat actually produced from the HCL-NaOH reaction assuming that the heat capacity of a 1M NaCl solution is 3.93 J/gC (celsius)
2) Moles of water formed in the reaction.
3) Total theoretical heat expected to be produced by forming the number of moles of water assumin that 57,320J are produced per mole of water formed.
4) Heat absorbed by the calorimeter
5) Heat capacity of the calorimeter ( heat absorbed by the calorimeter per degree of temperature change)
Explanation / Answer
1)
miilimoles of HCL = 50*2.199 =109.95
millimoles of base = 2*54 =108
salf formed = 109.95 millimoles
Q = (28.44 *0.10995 ) (3.9 )(0.2)
= 5.052 J
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2) moles of H20 formed = 0.10995 moles
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3)
total heat sould be 0.1099 * 57320 = 6.302 J
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4)
diffeence = 5.052 - 6.302
= -1.25 J
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heat capacity = 6.25 J/ C
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