Use the data below to answer the questions. Keep in mind that the enthalpy of fo

Question

Use the data below to answer the questions.

Keep in mind that the enthalpy of formation of an element in its standard state is zero.

Substance 718.4 679.9 74.8 217.94 268.61 Use the data below to answer the questions. Keep in mind that the enthalpy of formation of an element in its standard state is zero. Compare the reaction for the "expansion" of methane with the reverse of the reaction that represents the standard enthalpy of formation. Which properties are the same for both reactions and which are different? The enthalpy change of reaction, the number of atoms of each element, the state of the carbon atoms, the state of the methane molecules-Which reactions are same or different Suppose that 0.650 mol of methane, m CH_4(g), is reacted with 0.800 mol of fluorine, m F_2(g), forming m CF_4(g) and m HF(g) as sole products. Assuming that the reaction occurs at constant pressure, how much heat is released? Express your answer numerically in kilojoules.

Explanation / Answer

Expansion of methane

CH4 = C+4H

Enthalpy= +74.8 kJ

*********************************************************

CH4 +4F2 =CF4 +4 HF

0.2 0.8 0.2 0.8

Here, Fluorine will be the limitin product,

Ch4 used=0.2

Heat released=-(0.8*268.61+0.2*679.9)-(0.8*0-0.2*74.8)

=-335.908 KJ

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