In the reaction 2 B + 3 H 2 -> B 2 H 6 , if starting with 0.404 moles of B and 0

Question

In the reaction 2 B + 3 H2 -> B2H6, if starting with 0.404 moles of B and 0.612 moles of H2, which is the limiting reactant? 1. Neither. This is not a limiting reactant case 2. Boron 3. Hydrogen In the reaction 2 B + 3 H2 -> B2H6, if starting with 0.404 moles of B and 0.612 moles of H2, which is the limiting reactant? 1. Neither. This is not a limiting reactant case 2. Boron 3. Hydrogen 1. Neither. This is not a limiting reactant case 2. Boron 3. Hydrogen 1. Neither. This is not a limiting reactant case 2. Boron 3. Hydrogen

Explanation / Answer

For 0.612 moles of H2, we need (0.612/3)*2=0.408 moles of Boron

But we just have 0.404 moles of Boron, so Boron is the limiting reactant

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.