hree gases, nitrogen , argon , and methane are confined in a 10.0 L vessel at a

Question

hree gases, nitrogen, argon, and methane are confined in a 10.0 L vessel at a pressure of 9.00 atm. The vessel contains 4.00 moles of nitrogen, 5.00 moles of argon, and 4.00 moles ofmethane. What is the partial pressure of methane?

Partial pressure of methane = atm

Now suppose that 7.00 moles of neon are added to the vessel without changing the volume or temperature. What is the partial pressure of methane now?

Partial pressure of methane after addition of neon = atm

Now suppose that an additional 4.00 moles of methane are added to the vessel, again without any change in the volume or the temperature. What is the partial pressure of methane now?


Partial pressure of methane after addition of 4.00 more moles of methane = atm

Explanation / Answer

partial pressure = molf fraction x Total pressure

partial presuure of methane = [( 4)/(4+5+4) ] x 9 = 2.77 atm

neon 7 moles added at const Vol , temp hence Total pressure changes

PV = nRT , hence P2/P1 = n2/n1 , P2/9 = ( 4+5+4+7)/(4+5+4)   , P2 =13.846

after addition of Neon partial pressure of methane = [( 4/4+5+4+7)] x 13.846 = 2.77 atm

after 4 more moles of methane added

P2 = 9 x ( 4+5+4+4)/(4+5+4) = 11.77 atm

partial pressure of methane = ( 8/4+5+4+4) x 11.7 = 5.5 atm

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