I need help with my chemistry homework please: Thank you so much Part B An ideal

Question

I need help with my chemistry homework please:

Thank you so much

Part B An ideal gaseous reaction occurs at a constant pressure of 40.0atmand releases 70.5kJ of heat. Before the reaction, the volume of the system was 9.00L . After the reaction, the volume of the system was 2.60L. Calculate the total internal energy change. DeltaU. in kilojoules. Express your answer with the appropriate units. State functions versus path functions The change in internal energy. deltaU. is a state function because it depend only on the initial and final states of the system, and not on the path of change. In contrast, q and w are path functions because they depend on the path of change and not just the initial and final states of the system. Part C An ideal gas is confined to a container with a massless piston at the top. (Figure 2) A massless wire is attached to the piston. When an external pressure of 2.00 atmis applied to the wire, the gas compresses from 6.60 to 3.30L. When the external pressure is increased to 2.50 atm, the gas further compresses from 3.30 to 2.64L. In a separate experiment with the same initial conditions, a pressure of 2.50 atmwas applied to the ideal gas. decreasing its volume from 6.60 to 2.64L in one step. If the final temperature was the same for both processes, what is the difference between q for the two-step process and q for the one-step process in joules?

Explanation / Answer

dQ=dU+dW

dW=40*10^5*(2.6-9)*10^-3=25600J=-25.6kJ

dQ=+70.5kJ

dU=dQ-dW=96.1kJ

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