CH 3 -CH=N-H (g) + H 2(g) --> CH 3 -CH 2 -NH 2(g) Bond Bond enthalpy (kJ/mol) C=
ID: 795918 • Letter: C
Question
CH3-CH=N-H(g) + H2(g) --> CH3-CH2-NH2(g)
Bond
Bond enthalpy (kJ/mol)
C=N
615
C-N
276
H-H
436
N-H
393
C-H
414
Bond
Bond enthalpy (kJ/mol)
C=N
615
C-N
276
H-H
436
N-H
393
C-H
414
Explanation / Answer
CH3-CH=N-H(g) + H2(g) => CH3-CH2-NH2(g)
DH(reaction) = Bond energy of reactants - Bond energy of products
= 4 x C-H + 1 x C-C + 1 x C=N + 1 x N-H + 1 x H-H - 5 x C-H - 1 x C-C - 1 x C-N - 2 x N-H
= 1 x C=N + 1 x H-H - 1 x C-H - 1 x C-N - 1 x N-H
= 1 x 615 + 1 x 436 - 1 x 414 - 1 x 276 + 1 x 393
= -32 kJ/mol
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