Please Show Work if possible A. Calculate deltaGrxn for the reaction below at 25

ID: 796421 • Letter: P

Question

Please Show Work if possible

Calculate deltaGrxn for the reaction below at 25C

2Ca(s) + O2(g) = 2CaO(s)

given:

deltaH'rxn= -1270.2 kJ

deltaS'rxn= -211.9J/K

a) -1058.3 kj b) -1207.0 kj c) -1333.4 d) -1482.1 kj

Given that

C(s) + O2(g) = CO2(g) DeltaG'= -394.4 kj

CO(g) + 1/2O2(g) = CO2(g) DeltaG'= -257.2kj

Calculate deltaG' for the following reaction.

2C(s) + O2(g) = 2CO(g)

a) -651.6 kJ b) -274.4 kJ c) -137.2 kJ d) +137.2 kJ e) +274.4 kJ

For a chemical system deltaS' and deltaS are equal when

a) the system is in equilibrium.

b) the reactants and products are in standard state conditions.

c) deltaG' and delta G are both positive.

d) the reactants are elements.

e) the reactants and products are in the gas phase.

This is a simple gibbs energy equation

where delta g = deltaH - T * deltaS

therefore, deltaG = -1270200 - (298) (-211.9) = -1207053.8kJ = b). -1207.0 kJ

2).This is a hess law question

C + O2 --> CO2 ---(1).

CO + 1/2 O2 --> CO2 ---(2).

To get 2C + O2 --> 2CO as final equation

we add 2* (1) - 2 *(2) which cancels out 2 CO2 and 1 O2 molecule to give the fuinal equation

delta G follows the same rule as the equations

Therefore Delta G (net) = 2 * delta G1 - 2 * delta G2 = - 274.4 kJ

if delta S' and delta S are equal

it implies that

the system is in equilibrium

Rest all the options are false.

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